(X^2-y^2)(x^2+2xy)+(x^2-y^2)(y^2)=

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Solution for (X^2-y^2)(x^2+2xy)+(x^2-y^2)(y^2)= equation: 


Simplifying
(X2 + -1y2)(x2 + 2xy) + (x2 + -1y2)(y2) = 0

Reorder the terms:
(X2 + -1y2)(2xy + x2) + (x2 + -1y2)(y2) = 0

Multiply (X2 + -1y2) * (2xy + x2)
(X2(2xy + x2) + -1y2 * (2xy + x2)) + (x2 + -1y2)(y2) = 0
((2xy * X2 + x2 * X2) + -1y2 * (2xy + x2)) + (x2 + -1y2)(y2) = 0
((2xyX2 + x2X2) + -1y2 * (2xy + x2)) + (x2 + -1y2)(y2) = 0
(2xyX2 + x2X2 + (2xy * -1y2 + x2 * -1y2)) + (x2 + -1y2)(y2) = 0
(2xyX2 + x2X2 + (-2xy3 + -1x2y2)) + (x2 + -1y2)(y2) = 0

Reorder the terms:
(2xyX2 + -2xy3 + x2X2 + -1x2y2) + (x2 + -1y2)(y2) = 0
(2xyX2 + -2xy3 + x2X2 + -1x2y2) + (x2 + -1y2)(y2) = 0

Reorder the terms for easier multiplication:
2xyX2 + -2xy3 + x2X2 + -1x2y2 + y2(x2 + -1y2) = 0
2xyX2 + -2xy3 + x2X2 + -1x2y2 + (x2 * y2 + -1y2 * y2) = 0
2xyX2 + -2xy3 + x2X2 + -1x2y2 + (x2y2 + -1y4) = 0

Combine like terms: -1x2y2 + x2y2 = 0
2xyX2 + -2xy3 + x2X2 + 0 + -1y4 = 0
2xyX2 + -2xy3 + x2X2 + -1y4 = 0

Solving
2xyX2 + -2xy3 + x2X2 + -1y4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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